Study of the material release during PHÉBUS FPT-1 bundle phase with MELCOR 2.2

Piotr Darnowski , Mateusz Włostowski , Michał Stępień , Grzegorz Niewiński

Abstract

Study of the Phébus FPT-1 experiment with MELCOR 2.2.11932 severe accident integral computer code is presented. The developed model and simulations cover the fuel bundle phase up to 20,000 s after the test initiation. The paper is focused on the assessment of material released from the bundle with emphasis on radioactive releases. The core degradation, thermal-hydraulics, hydrogen production and structural material releases are also studied as coupled phenomena. Simulations are compared with experimental results and selected solutions available in the literature. Parametric sensitivity calculations were performed for selected modelling parameters influencing releases. Especially, the CORSOR-Booth model revisions are compared and assessed. Radioactive releases for MELCOR 2.1 and 2.2 are compared. New modelling parameters for molybdenum and Ag-In-Cd released as pseudo fission products are presented. A satisfactory agreement was obtained, confirming the validity of the developed model and efficiency of the new MELCOR2.2 code for the FPT-1 test.
Author Piotr Darnowski (FPAE / IHE)
Piotr Darnowski,,
- The Institute of Heat Engineering
, Mateusz Włostowski
Mateusz Włostowski,,
-
, Michał Stępień (FPAE / IHE)
Michał Stępień,,
- The Institute of Heat Engineering
, Grzegorz Niewiński (FPAE / IHE)
Grzegorz Niewiński,,
- The Institute of Heat Engineering
Journal seriesAnnals of Nuclear Energy, ISSN 0306-4549
Issue year2020
Vol148
Pages
Article number107700
Keywords in EnglishFission products, FPT-1ISP-46, MELCOR, Phebus, Source term
ASJC Classification2104 Nuclear Energy and Engineering
DOIDOI:10.1016/j.anucene.2020.107700
Languageen angielski
Score (nominal)100
Score sourcejournalList
ScoreMinisterial score = 100.0, 30-09-2020, ArticleFromJournal
Publication indicators WoS Citations = 0; Scopus SNIP (Source Normalised Impact per Paper): 2018 = 1.787; WoS Impact Factor: 2018 = 1.38 (2) - 2018=1.567 (5)
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